Jun 15 2010

Muonic States

Published by at 6:04 am under Quantum Mechanics

In converting the graviton energy to mass, we can apply 5.011 x 10-11 J = mgc2, or mg = 5.575 x 10-28 kg, though due to relativistic effects the graviton is never converted completely to mass in the natural world.  The muon mass, mμ = 207 me = 1.86 x 10-28 kg ([1], Compl. Av, 4.c., pg 527), is mg/3 and mp/9, where mp is the mass of the proton.

To quote the Frenchmen: “A muon μ which has been slowed down in matter can be attracted by the Coulomb field of an atomic nucleus and can form a bound state with the nucleus.” ([1], Compl. Av, 4., pg 525).  Before going any further then, and at the risk of sounding trite, like the quark and positron, the muon’s real identity may be that of a graviton.

Taking the concept of mass further, a conjugate wave graviton would slow down much more when passing through a proton or another nucleus than when it passes through an electron.  This increased compaction helps explain why the proton mass is 1836.5 times the electron mass.

Again relating to the muon, “the spread of the ground state, if the well were perfectly parabolic, would be on the order of: √(ћ/(2mμω)) ≈ 4.7 x 10-13 cm” ([1], Compl. Av, 4.c., pg 528).  This of course is very close to the wavelength of a free graviton: 3.965 x 10-13 cm.

The frequency of a muon is also close to that of a graviton:

ω ≈ 1.3 x 1022 rad. sec-1  ([1], Compl. Av, 4.c., pg 527),

whereas equivalent units for a graviton come out as:

ωg = (7.562 x 1022 Hz) (2π rad/cycle) = 4.75 x 1023 rad. sec-1

It cannot be overlooked that the rotational component of a conjugate wave graviton passing through a fundamental particle may be zero when considering gravity alone.  Similar to the metal pump tops sold in the ‘50’s and ‘60’s, of which I remember operating one as a boy, the pump action is linear and the top spin rotational.  Should there be a rotational action of a pass through graviton, it may be related only to Coulomb field production.  This Coulomb field action, produced by charge, is in total balance.  Griffiths states it this way: “… plus and minus charges occur in exactly equal amounts, to fantastic precision, in bulk matter, so that their effects are almost completely neutralized.  Were it not for this, we would be subjected to enormous forces: a potato would explode violently if the cancellation were imperfect by as little as one part in 1010.” ([2], pg xiv)

While it is difficult to find in books or on the web how fast the Coulomb force is transmitted, my guess is that it is nearly instantaneous, transmitting through the gravitational field in wave packets at group velocity, by phase shift and chirality, the combination of which determines positive and negative charge.


[1] Cohen-Tannoudji, Dui, Laloë, Quantum Mechanics, Hermann, 1977, Paris, France

[2] Griffiths, David J., Introduction to Electrodynamics, Third Edition, c. 1999, Prentice-Hall, Inc.

4 responses so far

4 Responses to “Muonic States”

  1. Carlon 22 Jun 2010 at 12:33 pm

    This question is off-topic, but can your theory explain gravitational lensing?

  2. Kevinon 22 Jun 2010 at 8:52 pm

    Gravitational lensing is explained in my April 2007 paper under Light bending vector analysis. I seem to remember diagramming it before writing that. If I knew how to place a figure on this web site, maybe it could be diagrammed again.

  3. Carlon 20 Jul 2010 at 10:30 am

    That is just what I was looking for, thanks! A diagram would be very interesting, but I don’t know what would be the best way to add it here. Google has a free image hosting service called Picasa (picasaweb.google.com). No pressure to add the diagram but if you would like to maybe that would help. A note if you use Picasa: you don’t need to download google’s Picasa program in order to upload images and use the online portion of the service; you can just upload via the site in a web browser.

  4. Kevinon 21 Jul 2010 at 7:30 am

    Maybe I will try that. Can still learn new technology, just not at the rate of you young people!

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