{"id":39,"date":"2008-03-09T21:33:02","date_gmt":"2008-03-10T02:33:02","guid":{"rendered":"http:\/\/www.fruechtetheory.com\/blog\/2008\/03\/09\/energy-balance-necessary-for-gravity-to-work\/"},"modified":"2011-03-12T13:07:47","modified_gmt":"2011-03-12T18:07:47","slug":"energy-balance-necessary-for-gravity-to-work","status":"publish","type":"post","link":"https:\/\/www.fruechtetheory.com\/blog\/2008\/03\/09\/energy-balance-necessary-for-gravity-to-work\/","title":{"rendered":"Energy Balance Necessary for Gravity to Work"},"content":{"rendered":"<p>Does an electron swell slightly with mass in the gravitational field of the earth as it scoops up gravitons while traveling in a quantum orbital toward the earth?\u00a0 Does it then give off multiple gravitons as it makes its next turn?\u00a0 If so, my guess is that they all fly off with one flip of the electron. \u00a0Certainly a slightly more massive electron will need additional momentum balance as it makes a turn, than an electron that is less massive. \u00a0I would estimate that an electron in an atomic orbital is never at a point where it cannot accept any more gravitons, because otherwise we could not use the gravitational constant so consistently.<br \/>\nSince the electron is traveling at maybe 0.2c in an atomic orbital, it can scoop up gravitons a lot more often than the nucleus must deflect them by its magnetic field, if that is what the nucleus does.\u00a0 Since a magnetic field does no work, it is the electric fields and currents inside a nucleus, &#8211; those also producing the internal nuclear forces, that would expend the energy to deflect gravitons.\u00a0 It must then recover that energy through the Coulomb field, which would then recover its energy through the gravitational field.\u00a0 This is an interesting concept because of the unification principles involved.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Does an electron swell slightly with mass in the gravitational field of the earth as it scoops up gravitons while traveling in a quantum orbital toward the earth?\u00a0 Does it then give off multiple gravitons as it makes its next turn?\u00a0 If so, my guess is that they all fly off with one flip of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"class_list":["post-39","post","type-post","status-publish","format-standard","hentry","category-quantum-mechanics"],"_links":{"self":[{"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/posts\/39","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/comments?post=39"}],"version-history":[{"count":1,"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/posts\/39\/revisions"}],"predecessor-version":[{"id":327,"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/posts\/39\/revisions\/327"}],"wp:attachment":[{"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/media?parent=39"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/categories?post=39"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.fruechtetheory.com\/blog\/wp-json\/wp\/v2\/tags?post=39"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}